A jar of gumballs contains 10 blue gumballs, 20 green gumballs, 15 yellow gumballs, and 25 pink gumballs. You reach into the jar and randomly select a gumball, then select another while replacing the first gumball back. What is the probability that you draw a green gumball as a percent and a fraction in simplest form?

There are 20 greens in 70 gumballs

The chance of drawing zero green ones is 50/70 * 49/69

To find the probability of drawing a green gumball, we'll need to determine the total number of possible outcomes and the number of favorable outcomes.

In this case, there are a total of 70 gumballs in the jar (10 blue + 20 green + 15 yellow + 25 pink). Since you're replacing the first gumball back into the jar before selecting the second one, the total number of possible outcomes remains constant for both draws.

The number of favorable outcomes would be the number of green gumballs, which is 20.

To find the probability, you can use the formula:

Probability = Number of Favorable Outcomes / Total Number of Possible Outcomes

Probability = 20 / 70

To express this as a percentage, divide the number of favorable outcomes by the total number of possible outcomes and multiply by 100:

Probability as a percent = (20 / 70) * 100 ≈ 28.57%

To express this as a fraction in simplest form, you can reduce the fraction 20/70:
- Both 20 and 70 are divisible by 10, so you can divide both the numerator and denominator by 10.
- 20 ÷ 10 = 2
- 70 ÷ 10 = 7

Thus, the probability of drawing a green gumball is 2/7 in simplest form.