The radius of a roll of paper is 7.6 cm and its moment of inertia is I = 2.9 × 10^3 kg·m2. A force of 3.2 N is exerted on the end of the roll for 1.3 s, but the paper does not tear so it begins to unroll. A constant friction torque of 0.11 m·N is exerted on the roll which gradually brings it to a stop. Assume that the paper's thickness is negligible.

a.) Calculate the length of paper that unrolls during the time that the force is applied (1.3 s)
b.) the length of paper that unrolls from the time the force ends to the time when the roll has stopped moving

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  1. τ t = ΔIω
    Solve for ω
    θ = ωt
    and s = rθ
    Same technique for part two with new τ

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  2. 67

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