A rectangular fence has a perimeter of 1080 feet. The length is 3 feet more than twice the width. What are the dimensions?

361ft x 179ft

86

To solve this problem, we can use algebraic equations.

Let's assume that the width of the rectangle is "W" feet. According to the problem, the length of the rectangle is 3 feet more than twice the width, which can be expressed as "2W + 3" feet.

The perimeter of a rectangle is given by the formula: P = 2(L + W), where P is the perimeter, L is the length, and W is the width. In this case, we know that the perimeter is 1080 feet, so we can write the equation as:

1080 = 2(2W + 3 + W)

Simplifying the equation:

1080 = 2(3W + 3)

Dividing both sides of the equation by 2:

540 = 3W + 3

Subtracting 3 from both sides:

537 = 3W

Dividing both sides by 3:

179 = W

So, the width of the rectangle is 179 feet.

To find the length, we can substitute the value of W into the expression for the length, which is "2W + 3":

Length = 2(179) + 3
Length = 358 + 3
Length = 361 feet

Therefore, the dimensions of the rectangular fence are 179 feet for the width and 361 feet for the length.