math

2. A candy machine has 10 grape, 6 green apple, and 16 mango gumballs. What is the probability of selecting a grape and a mango gumball as fraction in simplest form and a percent?

P(A and B) = P (A) * P (B)

10/32 * 16/32 = 80/512 = 5/32 simplest form

Percent: 15.625%

The probability of choosing a grape and a mango gumball is 5/32 or 15.625%.


asked by May someone please check my work and answer ASAP?
  1. That depends :(

    If you do not put the grape back, you only have 31 in the machine when you draw the mango.

    You assumed the two events were independent. They may not be.
    I would have said:
    10/32 * 16/31 not 32

    posted by Damon
  2. So it's dependent event because you don't replace it, so instead of having a total of 32 it's 31?

    posted by Anonymous

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