If the column of water in the water bormeter rose to a height of 35 feet, what would the atmospheric pressure be in mm Hg?
I believe it is
(35 ft/density Hg) x (12 in/ft) x (25.4 mm/in) = ??. This neglects the vapor pressure of water that will be pushing down inside the water barometer.
(35ft/1)x(12in/1ft)x(25.4mm/1in) = 10,668 mmH2O
using mmH2O x (density H2O/density Hg) = mmHg
10,668 mmH2O x (0.99707g/mL / 13.5340g/mL) 785.9 mmHg
If the column of water in the water barometer rose to a height of 33 feet, what would the atmospheric pressure be in mm Hg?
column of water in the water barometer rose to a height of 33 feet, what would the atmospheric pressure be in mm Hg?
mm Hg
To determine the atmospheric pressure in mm Hg, we can use the conversion factor that 1 mm Hg is equal to 13.6 mm of water. Here's how you can calculate it:
1. Convert the height of the water column from feet to mm:
- Since 1 ft is equal to 304.8 mm, multiply the height (35 ft) by 304.8 to convert it to mm:
35 ft * 304.8 mm/ft = 10668 mm
2. Divide the height in mm by the conversion factor (13.6 mm Hg/mm):
- Divide 10668 mm by 13.6 mm Hg/mm:
10668 mm / 13.6 mm Hg/mm ≈ 784.12 mm Hg
So, if the column of water in the barometer rises to a height of 35 feet, the atmospheric pressure would be approximately 784.12 mm Hg.