3 equal charges each of of 2*10-6 C are fixed at three corners of an equilateral triangle ofsides 5 cm.find the column force experienced by one of the charge due to the rest two.

To find the Coulomb force experienced by one of the charges due to the rest two charges, we can use the formula for electrostatic force:

F = k * (|q1| * |q2|) / r^2

Where:
- F is the electrostatic force,
- k is the electrostatic constant (k = 9 * 10^9 Nm^2/C^2),
- q1 and q2 are the magnitudes of the charges involved,
- r is the distance between the charges.

In this case, we have three equal charges of magnitude 2 * 10^-6 C arranged in an equilateral triangle.

Step 1: Calculate the distance between the charges.
Since we have an equilateral triangle, each side of the triangle is 5 cm. The distance between the charges is the length of the sides of the triangle. Therefore, the distance is 5 cm.

Step 2: Calculate the electrostatic force.
Using the formula mentioned above, we can calculate the electrostatic force between two charges. However, there are two other charges present which will exert a force on the charge in question. Hence, we need to calculate the electrostatic force due to each charge and then find the net force.

The force due to one charge when it is repelled by another identical charge is given by:
F1 = k * (|q1| * |q2|) / r^2

We can see that F1 = F2 = F3 since the charges are identical, and the distance between them is the same. Therefore, the net force is given by:
F_net = F1 + F2 + F3

Substituting the given values:
F_net = (k * (2 * 10^-6 C)^2) / (0.05 m)^2

Calculating:
F_net = (9 * 10^9 Nm^2/C^2) * (4 * 10^-12 C^2) / (0.05 m)^2

Simplifying:
F_net = (9 * 10^9 Nm^2) * (4 * 10^-12 C^2) / (0.05^2 m^2)

F_net = (9 * 4 * 10^-3 Nm^2) / 0.0025 m^2

F_net = 1.44 * 10^6 N

So, the net force experienced by one of the charges due to the rest two charges is approximately 1.44 * 10^6 Newtons.

To find the electrical force experienced by one charge due to the rest two charges in an equilateral triangle, we can use Coulomb's Law.

Coulomb's Law states that the electrical force between two charges is given by the formula:

F = k * (q1 * q2) / r^2

Where:
F is the electrical force between the charges
k is the electrostatic constant, approximately equal to 9 x 10^9 Nm^2/C^2
q1 and q2 are the magnitudes of the charges
r is the distance between the charges

In this case, we have three equal charges of 2 x 10^-6 C each arranged in an equilateral triangle of side length 5 cm. Now, let's calculate the force experienced by one charge due to the rest two.

Step 1: Calculate the distance between the charges.
In an equilateral triangle, the distance between any two charges at the corners is equal to the side length of the triangle.
Therefore, the distance between the charges is 5 cm.

Step 2: Use Coulomb's Law to calculate the electrical force.
Since the charges are equal, we can plug in the values into the formula:
F = (9 x 10^9 Nm^2/C^2) * (2 x 10^-6 C * 2 x 10^-6 C) / (0.05 m)^2

Step 3: Simplify the calculation.
F = (9 x 10^9 Nm^2/C^2) * 4 x 10^-12 C^2 / 0.0025 m^2
= (9 x 10^9 N * 4 x 10^-12 C^2) / 0.0025 m^2
= (36 x 10^-3 N) / 0.0025 m^2
= 14.4 N / 0.0025 m^2
= 5760 N/m^2

Therefore, the Coulomb force experienced by one charge due to the rest two charges is 5760 N/m^2.