A school store has 1,200 pencils in stock and sells and average of 25 pencils per day. The manager reorders when the number of pencils in stock is 500. Write and solve an equation to find out how many days will pass before the manager needs to order more pencils.

(1200 - 500) / 25 = d

The equation is -20x + 2,000 = 1,000

x = 50

To solve this problem, we can set up an equation using the given information and then solve for the number of days.

Let's assume "x" represents the number of days.

The number of pencils sold per day is given as an average of 25 pencils, so in "x" days, the number of pencils sold would be 25x.

The initial number of pencils in stock is 1,200, and we need to reorder when the number of pencils in stock is 500. So, the equation can be written as:

1,200 - 25x = 500

To solve this equation for "x," we can follow these steps:

1. Subtract 1,200 from both sides of the equation:
-25x = 500 - 1,200

2. Simplify the right side:
-25x = -700

3. Divide both sides of the equation by -25 to solve for "x":
x = -700 / -25
x = 28

Therefore, the manager needs to order more pencils after 28 days.

28