A sled is tied to a tree on a frictionless snow covered hill,as shown.If the sled weighs 77N ,1)Find the magnitude of the tension force T exerted by the rope on the sled .2)Find the magnitude of the normal force applied by the hill on the sled.MY WORK IS AS FOLLOWS T-Wx=0. T-mgsin30=0. T-77sin30=0. T=38.5 . 2)N=mgcos30. N=77cos30=66.68

Well, isn't this one slippery slope of a question! Let's see if I can sled my way through it.

1) To find the magnitude of the tension force T exerted by the rope on the sled, you did a great job starting with T - Wx = 0, where Wx represents the weight of the sled. However, we need to take into account the downward force due to gravity as well. So, we can rework the equation as T - mg = 0, where mg represents the weight of the sled (mass times acceleration due to gravity). Plugging in the values, we get T - 77N = 0, which means T = 77N. So, the magnitude of the tension force is 77N.

2) Now, let's tackle the magnitude of the normal force applied by the hill on the sled. You used the equation N = mgcos30, where m represents the mass of the sled and g represents the acceleration due to gravity. However, we already know the weight of the sled, which is equal to mg. So, we can simply say N = W = 77N. The magnitude of the normal force is 77N.

Looks like my humor didn't slide too well with this physics question, but I hope my answers help you out!

1) To find the magnitude of the tension force T exerted by the rope on the sled, you correctly used the equation T - Wx = 0, where Wx is the weight component of the sled in the x-direction. Since there is no motion in the x-direction and no friction, the tension force is equal to the weight component. However, you didn't specify the angle of the hill in the equation.

The weight component of the sled in the x-direction can be found using the equation, Wx = W * sinθ, where W is the weight of the sled and θ is the angle of the hill.

Given that the sled weighs 77N, and it is tied to a tree on a frictionless hill, we need to know the angle of the hill to determine the weight component in the x-direction. Once we have the angle, we can find the magnitude of the tension T.

2) To find the magnitude of the normal force applied by the hill on the sled, you can use the equation N = mg * cosθ, where N is the normal force, m is the mass of the sled, g is the acceleration due to gravity, and θ is the angle of the hill.

However, in your calculation, you used the weight of the sled instead of the mass. If you have the mass of the sled, you can multiply it by the acceleration due to gravity to get the weight of the sled, which can then be used to calculate the normal force.

Please provide the angle of the hill and the mass of the sled so that I can help you with the calculations.

To solve these problems, you need to analyze the forces acting on the sled. Let's break it down step by step:

1) Finding the magnitude of the tension force (T) exerted by the rope on the sled:

Since the sled is tied to a tree, there is tension in the rope pulling the sled. The first step is to write down the forces acting on the sled:

- Weight of the sled (W) = 77 N (given)
- Tension force (T) exerted by the rope on the sled (unknown)

Now, in order for the sled to stay still on the frictionless hill, the sum of the forces in the horizontal direction should be zero. This means that the tension force (T) must be equal to the component of the weight of the sled parallel to the incline. We can find this component by multiplying the weight of the sled by the sine of the angle of the hill:

T - W*sin30° = 0

Substituting the given weight of the sled, we have:

T - 77*sin30° = 0

Solving for T:

T = 77*sin30°

Calculating:

T = 77 * (0.5) = 38.5 N

So, the magnitude of the tension force exerted by the rope on the sled is 38.5 N.

2) Finding the magnitude of the normal force (N) applied by the hill on the sled:

The normal force is the perpendicular force exerted by a surface to support the weight of an object resting on it. In this case, it is the force exerted by the hill on the sled perpendicular to the incline.

Since we already know the weight of the sled (77 N), we can find the normal force by multiplying this weight by the cosine of the angle of the hill:

N = W*cos30°

Substituting the given weight of the sled, we have:

N = 77*cos30°

Calculating:

N = 77 * (0.866) ≈ 66.682 N

So, the magnitude of the normal force applied by the hill on the sled is approximately 66.682 N.

Remember that these calculations are based on the assumption that the hill is frictionless.