space for a roll of two number cubes is shown in the table.
(1,1)|(1,2)|(1,3)|(1,4)|(1,5),(1,6)
(2,1)|(2,2)|(2,3)|(2,4)|(2,5)|(2,6)
(3,1)|(3,2)|(3,3)|(3,4)|(3,5)|(3,6)
(4,1)|(4,2)|(4,3)|(4,4)|(4,5)|(4,6)
(5,1)|(5,2)|(5,3)|(5,4)|(5,5)|(5,6)
(6,1)|(6,2)|(6,3)|(6,5)|(6,5)|(6,6)
The two numbers rolled can be added to get a sum. Find P(sum is Less than 4).
A. 1/12••
B. 5/36
C. 2/9
D. 11/12
Correct me
looks good to me
Steve can you help me please i posted a ?
To find the probability (P) that the sum of the two number cubes is less than 4, we need to count how many outcomes satisfy this condition and divide it by the total number of possible outcomes.
In this case, the possible outcomes are all the combinations of numbers rolled on the two cubes, which is 6*6 = 36.
Now let's count the outcomes where the sum is less than 4. We have:
(1,1)
(1,2)
(2,1)
So there are 3 outcomes that satisfy the condition.
Therefore, the probability P(sum is less than 4) = 3/36 = 1/12.
The correct answer is A) 1/12.
To find the probability that the sum of the two number cubes is less than 4, we need to count the number of outcome pairs that satisfy this condition and divide it by the total number of outcome pairs.
From the table given, we can see that the possible sums less than 4 are (1,1), (1,2), (2,1), and (2,2). So, there are 4 outcome pairs that satisfy this condition.
The total number of outcome pairs is the product of the number of possible outcomes on each cube, which is 6 for each cube. So, there are 6 * 6 = 36 total outcome pairs.
Therefore, the probability (P) that the sum is less than 4 is:
P = Number of favorable outcomes / Total number of outcomes = 4 / 36 = 1/9
So, the correct answer is C. 1/9.