how many ml of 0.200m NAOH solution contain 2.00g NaOH(MW =40.00
I will assume that 0.200m is a typo and you mean 0.200 M.
mols NaOH = grams/molar mass = ?
Then M NaOH = mols NaOH/L NaOH. YOu know mols and M, solvle for L and convert to mL.
To determine the volume of the 0.200 M NaOH solution that contains 2.00 g of NaOH, we need to use the molarity and the molecular weight of NaOH.
First, let's convert the mass of NaOH to moles using the molecular weight:
number of moles = mass / molecular weight
number of moles = 2.00 g / 40.00 g/mol
number of moles = 0.05 mol
Now, we can use the definition of molarity to calculate the volume:
molarity = moles / volume in liters
We can rearrange this equation to solve for the volume:
volume = moles / molarity
volume = 0.05 mol / 0.200 mol/L
volume = 0.25 L
Since there are 1000 mL in 1 L, we can convert the volume to milliliters:
volume = 0.25 L * 1000 mL/L
volume = 250 mL
Therefore, 250 mL of the 0.200 M NaOH solution contains 2.00 g of NaOH.
To determine the volume of 0.200 M NaOH solution that contains 2.00 g of NaOH, we need to use the concept of molarity and the formula:
Molarity (M) = moles of solute / volume of solution in liters
First, let's calculate the number of moles of NaOH using the given mass and the molar mass:
moles = mass / molar mass
moles = 2.00 g / 40.00 g/mol
moles = 0.050 mol
Now we can use the formula for molarity to find the volume of the solution:
Molarity (M) = moles / volume
0.200 M = 0.050 mol / volume
We can rearrange the equation to solve for the volume:
volume = moles / Molarity
volume = 0.050 mol / 0.200 M
volume = 0.250 L
Finally, we convert the volume from liters to milliliters:
volume = 0.250 L * 1000 mL/L
volume = 250 mL
So, 2.00 g of NaOH will be dissolved in 250 mL of 0.200 M NaOH solution.