Question

Calculate value of Ksp for Ca(OH)2 (ΔG∘f(Ca2+)=-553.6 kJmol−1 , ΔG∘f(OH−)=-157.2 kJmol−1 , ΔG∘f(Ca(OH)2)=-898.5 kJmol−1 ).

Answer 1

Ca(OH)2 ==> Ca^2+ + 2OH^-

dGorxn = (dGo products)-(dGo reactants)
Then dGo = -RTlnKsp