the mass of the moon (assumed spherical ) is 7.35×10^22 its diamter is 3480 km find the escape velocity from the moon
G=6.67 × 10^-11 n/m^2/kg^2
To find the escape velocity from the moon, we need to use the law of universal gravitation and the formula for escape velocity.
The formula for escape velocity is:
ve = sqrt(2 * G * M / r)
Where:
ve = escape velocity
G = gravitational constant (6.67 × 10^-11 N/m^2/kg^2)
M = mass of the moon (7.35 × 10^22 kg)
r = radius of the moon (equals half the diameter, so 3480 / 2 = 1740 km = 1.74 × 10^6 m)
Now let's plug in the values and calculate the escape velocity:
ve = sqrt(2 * (6.67 × 10^-11) * (7.35 × 10^22) / (1.74 × 10^6))
Calculating this expression, we get:
ve ≈ 2.38 × 10^3 m/s
So, the escape velocity from the moon is approximately 2380 m/s.