What is the final speed of an object and how far does it travel while accclerating if its initial speed is 10m/s and it accelerates at 8.9m/s squared for 5 s

To find the final speed of an object and the distance it travels while accelerating, you can use the following kinematic equations of motion:

1. Final Velocity (Vf) = Initial Velocity (Vi) + (Acceleration * Time)
2. Distance (d) = (Initial Velocity * Time) + (0.5 * Acceleration * Time^2)

Given:
Initial velocity (Vi) = 10 m/s
Acceleration (a) = 8.9 m/s^2
Time (t) = 5 s

To find the final velocity (Vf):
Using equation 1:
Vf = Vi + (a * t)
Vf = 10 m/s + (8.9 m/s^2 * 5 s)
Vf = 10 m/s + 44.5 m/s
Vf = 54.5 m/s

The final velocity of the object is 54.5 m/s.

To find the distance traveled (d):
Using equation 2:
d = (Vi * t) + (0.5 * a * t^2)
d = (10 m/s * 5 s) + (0.5 * 8.9 m/s^2 * (5 s)^2)
d = 50 m + (0.5 * 8.9 m/s^2 * 25 s^2)
d = 50 m + 111.25 m
d = 161.25 m

The object travels a distance of 161.25 m while accelerating.