physics

A 10 kg crate is pulled up a rough incline with an initial speed of 1.5 m/s. The pulling force is 100 N parallel to the incline, which makes an angle of 20 degrees with the horizontal. If the coefficient of kinetic friction is .40 and the crate is pulled a distance of 5 m, (a) how much work is done by gravitational force? (b) How much work is done by the 100 N force? (c) What is the change in kinetic energy of the crate? (d) What is the speed of the crate after it is pulled 5m?

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  1. friction force down the plane:
    mu*mg*Cos20
    gravity force down the plane:
    mg*sin20
    work done by 100N force:
    100*5=500J
    work=force*distance
    a. work done by gravity:
    mg*sin20*(-5)=-5mg*sin20
    b. work done by 100N force:
    500J
    c.KE change:
    500J-5mg*sin20-mu*mg*cosTheta*5
    d. speed final
    1/2 m v^2=KEchange
    solve for v

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    bobpursley

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