what is the greatest perimeter of a rectangle with an area of 39 square feet

there is no limit.

There must be some other considerations.

well it said on my homework

Do the dimensions have to be in whole numbers?

Well, your homework is poorly stated.

Here is an example of what Steve is saying:

suppose the width is .1 ft
then the length = 39/.1 or 390 ft
perimeter = 2(390) + 2(.1) = 780.2 ft

check: area = .1(390) = 39

suppose the width is .001 ft
then the length is 39/.001 or 39000 ft
perimeter = 2(39000) + 2(.001) = pretty big

As you can see we can make the perimeter as large as we want to by making the width smaller and smaller, and still keep an area of 39

I had it on my homework too.

My Work said

What is the greatest perimeter that you can make with a rectangle that has an area of 24 square units? Draw and label all of your attempts below. Be sure that your final solution has the largest perimeter.

To find the greatest perimeter of a rectangle with an area of 39 square feet, we need to determine the dimensions of the rectangle first.

Since the area of a rectangle is calculated by multiplying its length by its width, we can try different combinations of length and width to find the one that yields the greatest perimeter.

Let's start by listing all the factors of 39: 1, 3, 13, and 39.

Now, let's try each factor as the length of the rectangle and divide 39 by that factor to find the corresponding width.

For example, if the length is 1, the width is 39. This gives us a perimeter of 2(1 + 39) = 80.

If the length is 3, the width is 13. This gives us a perimeter of 2(3 + 13) = 32.

Similarly, if the length is 13, the width is 3, giving us a perimeter of 2(13 + 3) = 32.

Lastly, if the length is 39, the width is 1, resulting in a perimeter of 2(39 + 1) = 80.

Comparing all these options, we see that the greatest perimeter is 80.

Therefore, the greatest perimeter of a rectangle with an area of 39 square feet is 80 feet.