What is the concentration of IO3- (total volume: 20mL) when you have .00001mol of HSO3- (total volume: 10mL)? Use the balanced equation IO3-(aq)+3HSO3-(aq)>>>I-(aq)+3SO4^2-(aq)+3H+(aq)
See your other post.
M = mols/L
To find the concentration of IO3-, we first need to determine the number of moles of IO3- in the reaction.
Given:
- Moles of HSO3- = 0.00001 mol
- Total volume of HSO3- solution = 10 mL
- Total volume of IO3- solution = 20 mL
From the balanced equation, we can see that the stoichiometric coefficient of IO3- is 1. This means that one mole of IO3- reacts with three moles of HSO3-.
Now we can calculate the number of moles of IO3-:
Moles of IO3- = (Moles of HSO3-) x (Stoichiometric coefficient of IO3-)
= 0.00001 mol x 1
= 0.00001 mol
Next, we need to calculate the concentration of IO3-. Concentration is defined as moles per liter (mol/L).
First, we convert the volume of IO3- solution from mL to L:
Volume of IO3- solution = 20 mL = 20/1000 L = 0.02 L
Finally, we can calculate the concentration of IO3-:
Concentration of IO3- = (Moles of IO3-) / (Volume of IO3- solution)
= 0.00001 mol / 0.02 L
= 0.0005 mol/L
Therefore, the concentration of IO3- is 0.0005 mol/L.