How to find the moles of IO3- reacted when you have .00001mol of 10mL HSO3-? Using the equation IO3-(aq)+3HSO3-(aq)>>>I-(aq)+3SO4^2-(aq)+3H-(aq)
This is just a coefficient ratio.
0.00001 mol HSO3^- x (1 mol IO^-)/ mol HSO3^-) = 0.00001 x 1/3 = ?
To find the moles of IO3- that reacted, we can use stoichiometry and the given information.
Given:
- 0.00001 mol of HSO3-
- Balanced equation: IO3-(aq) + 3HSO3-(aq) >>> I-(aq) + 3SO4^2-(aq) + 3H-(aq)
To find the moles of IO3- reacted, we need to use the molar ratio of IO3- to HSO3- from the balanced equation.
Molar Ratio:
From the balanced equation, we can see that 1 mole of IO3- reacts with 3 moles of HSO3-. Therefore, the molar ratio of IO3- to HSO3- is 1:3.
Now, let's calculate the moles of IO3- reacted:
1. Determine the number of moles of HSO3-:
Given that there are 0.00001 mol of HSO3-, there are also 0.00001 mol of IO3- reacted (using the 1:3 molar ratio).
2. Convert the moles of IO3- to the volume in liters:
To convert the moles of IO3- reacted to the volume in liters, we need to use the formula:
Volume (L) = Moles / Molarity
We have the moles of IO3- reacted (0.00001 mol), but we need to determine the molarity.
To do so, we need to know the volume of the solution and the concentration of the solution.
Given that 10 mL (0.01 L) of HSO3- solution was used, we need to determine the concentration (molarity) of the HSO3- solution.
Once we have the concentration (molarity), we can use it to calculate the volume of IO3- reacted.
Please provide the concentration (molarity) of the HSO3- solution, and I will help you calculate the volume of IO3- reacted.