The water level in a spherical bowl has a diameter of 30cm. If the horizontal diameter of the bowl is 10cm below the water level. calculate the radius of the bowl and the depth of the water in the bowl.

Let the radius be r

R^2=5^2+15^2
R =√250
R =15.8

Depth of water = 5 + 15.8
= 20.8

sketch a cross-section, and complete the right-angled triangle

let the radius be r
r^2 = 10^2 + 15^2
r = √325

depth of water = 10 + √325
= ...

18.303

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The water level in a spherical bowl has a diameter of 30cm. If the horizontal diameter of the bowl is 10cm below the water level. calculate the radius of the bowl and the depth of the water in the bowl.

Please I want to see how the diagram is on this question

Please I want to see the diagram to this question answered above

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