The Little Lion's water cooler was filled with 255.5 ounces of water. The cooler's tap is emptying out 0.3 ounces of water per second. In how many seconds will the cooler be 40% full?
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.6 * 255.5 = 153.3 leaked out
.3 oz/s * t = 153.3 oz
t = 153.3 /0.3 = 511 seconds
To find out how many seconds it will take for the water cooler to be 40% full, we need to calculate how much water is equivalent to 40% of the total capacity of the water cooler.
The total capacity of the water cooler is given as 255.5 ounces of water.
To find 40% of the total capacity, we can use the formula: (40/100) * total capacity = 0.4 * 255.5 = 102.2 ounces.
Now, we need to determine how long it will take for the water cooler to have 102.2 ounces of water considering that it is emptying out at a rate of 0.3 ounces per second.
We can set up an equation: rate * time = 102.2, where rate is the emptying rate in ounces per second and time is the number of seconds.
So, rearranging the equation, we have: time = 102.2 / rate.
Plugging in the values, we get: time = 102.2 / 0.3 ≈ 340.67 seconds.
Therefore, it will take approximately 340.67 seconds for the water cooler to be 40% full.