The population of a colony of frogs under ideal condition double every 10 days. Solve the the equation 2 raised to the power of n equals 50 (2^n =50)to work out how many 10 days period it takes for the population to be 50 times as large as it is now. Hence, write down this time to the nearest day.

2^n = 50. n*Log2 = Log50, n = Log50/Log2 = 5.64 or 6 10-day periods to reach 50 times current

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