Each of two urns contains green balls and red balls. Urn I contains 8 green balls and 12 red balls. Urn II contains 5 green balls and 8 red balls. If a ball is drawn from each urn, what is P(red and red)?
A. 79/65
B. 24/65
C. 20/33*
D. 2/13
You have six $1 bills, eight $5 bills, two $10 bills, and four $20 bills in your wallet. You select a bill at random. Without replacing the bill, you choose a second bill. What is P($1, then $10)?
A. 77/190*
B. 3/100
C. 3/95
D. 2/5
A true-false test has 12 questions. What is the probability of guessing the correct answers to all of the questions?
A. 1/4096
B. 1/144*
C. 1/24
D. 1/14
Please check these. If I'm incorrect, please help because I'm very stumped. :-( Thank you very much!
For the first one, I think it is B
P(red and red) = 12/20 * 8/13
(Don't forget to add the total number of balls)
Second one is C
P(1 then 10) = 6/20 * 2/19
Since you take one note without replacing, the total number of notes is reduced by 1 from 20 to 19
The third one is A
P(one question right) = 1/2
(2 options, T or F)
P(12 questions right) = 1/2 * 12
I would Multiply 1/2 by 12 (instead of add 1/2 12 times)here because it is in one whole test paper (haha not too sure how to explain, if it is confusing, just ignore it)
Hope this helps!
His name is Saitama
DaKoolKid...thanks but unfortunately, many of your answers seem incorrect :/
she is not she has posted these answers in many different questions on here and everyone has said that her answers are wrong. do not follow lady usanes answers
i read that as watch dragon balls lol
y u takin credit of other peopls speech mf
no. u can stay clueless mf
1)
prob(r,r) = (12/20)(8/13) = 24/65 ----> B
2)
prob = (6/20)(2/19) = 3/95 ----> C
3)
you want (1/2)^12 = 1/4096 ----> A