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A chemist has a solution that is 70% acid and another that is 45% acid. How many liters of each should he mix to obtain 300 liters of a solution that is 65% acid?

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asked by Brooke
  1. amount of the 70% solution --- x L
    amount of the 45% solution--- 300-x L

    .70x + .45(300-x) = .65(300)
    time 100
    70x + 45(300-x) = 65(300
    70x + 13500 - 45x = 19500
    25x = 6000
    x = 240

    So 240 L of the 70% stuff, and 60 L of the 45% stuff

    check:
    .7(240) + .45(60) = 195
    .65(300) = 195
    looks good to me

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    posted by Reiny

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