Find the Area:
f(x)=sin6x and g(x) = cos 12x, -pi/12 less than or euqal to x is less than or equal to pi/36
Wolfram shows that x = -π/12 and π/36 are intersection values and the region forms a closed area.
area = ∫(cos 12x - sin 6x) dx from -π/12 to π/36
= (1/12)sin 12x + (1/6)cos 6x | from -π/12 to π/36
= ..
take over