Math

A rocket is launched from the top of a 50 foot cliff with an initial velocity of 120 feet per second. The height, h, of the rocket after t seconds is given by the equation h=-16t^2 + 120t+ 50. How long after the rocket is launched will it be 10 feet from the ground?

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  1. just solve for t in

    -16t^2 + 120t+ 50 = 10

    probably the quadratic formula will be helpful.

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    posted by Steve

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