Darin has 5 coins that total 62 cents.what are the coins
2 quarters 2 pennies 1 dime
2pennies.two nickels. on 50cent piece.
no bobpursley. its 2 quarters, not one 50cent piece, a dime, not 2 nickels and yes, 2 pennies
2 quarters 1 dime 4 pennies
To find out what coins Darin has, we can use a bit of algebraic reasoning.
Let's assume that Darin has x number of pennies.
This means that he would have (5 - x) number of other coins.
A penny is worth 1 cent, and let's assume that the value of the other coins is y cents each.
Given that the total value of the coins is 62 cents, we can create an equation:
x + y(5 - x) = 62
Now, we can solve for x and y.
First, distribute y to 5 - x:
x + 5y - xy = 62
Rearrange the terms:
-xy + x + 5y = 62
Now, let's look at the possible values of x and y.
Since x represents the number of pennies, it can be any value from 0 to 5, as Darin has 5 coins in total.
For each value of x, we can substitute it back into the equation to find y.
Let's try different values of x:
If x = 0 (no pennies), the equation becomes:
-0y + 0 + 5y = 62
5y = 62
y = 12.40
Since y represents the value of the other coins and cannot be a decimal, this combination is not valid.
If x = 1 (one penny), the equation becomes:
-1y + 1 + 5y = 62
4y + 1 = 62
4y = 61
y = 15.25
Again, this combination is not valid.
If x = 2 (two pennies), the equation becomes:
-2y + 2 + 5y = 62
3y + 2 = 62
3y = 60
y = 20
This means Darin has two pennies and three coins worth 20 cents each.
Therefore, the coins that Darin has are 2 pennies and 3 nickels.