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given the quadratic equation expression x^2+10*x+12 find the turning point of its graph by using the technique known as completing the square.

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asked by @@prit
  1. let y = x^2 + 10x + 12
    = (x^2 + 10x + 25 - 25) + 12
    = ( (x+5)^2 - 25) + 12
    = (x+5)^2) - 25 + 12
    = (x+5)^2 - 13

    we have found the vertex to be (-5,-13), which for a parabola would be the turning point.

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    posted by Reiny

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