the sum of 2 numbers is 83. three times the smaller number is subtracted from the larger number is 19.
how do i set this problem up?
larger x
smaller y
x+y = 83
x - 3y = 19
subtract them:
4y = 64
y = 16 , then
x = 67
larger is 67, the smaller is 16
To set up this problem, we need to define the two unknown numbers and create equations based on the given information. Let's call the smaller number "x" and the larger number "y".
Given information:
1. The sum of 2 numbers is 83: x + y = 83
2. Three times the smaller number is subtracted from the larger number is 19: y - 3x = 19
Now, you have a system of two equations:
Equation 1: x + y = 83
Equation 2: y - 3x = 19
Using these equations, we can solve for both numbers simultaneously.