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A spring of natural length 1.5m is extended 0.0050m by a force of 0.8N, what will its length be when the applied force is 3.2N?

k = 0.8N/0.0050m = 160 N/m.

L = 1.5 + 3.5N*1m/160N. = 1.5219 m.

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