# Physics

A spring of natural length 1.5m is extended 0.0050m by a force of 0.8N, what will its length be when the applied force is 3.2N?

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1. k = 0.8N/0.0050m = 160 N/m.

L = 1.5 + 3.5N*1m/160N. = 1.5219 m.

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posted by Henry
2. 2*2356nm

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posted by praise
3. 19.936

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posted by FUNKE

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