Trig

Solve each equation for exact solutions over the interval [0,360)where appropriate. Round approximate solutions to the nearest tenth degree. Sin^2Theta=Cos^2Theta+1
My Work: Using double angle Identity I subtract 1 to other side therefore:
1-Sin^2theta=Cos^2theta= Cos2theta=Cos^2theta.

This is where I am stuck.For this does not conclude an answer...

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asked by Ronald
  1. since sin^2θ is never more than 1, you need cos^2θ = 0

    so, θ = π/2 or 3π/2

    or, solving algebraically,

    sin^2θ = cos^2θ + 1
    cos^2θ - sin^2θ = -1
    cos(2θ) = -1
    θ = π/2 or 3π/2

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    posted by Steve

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