Given that log x = 5.5 and log y = 3.8, evaluate
log (x2 y3)
I will assume you meant:
log(x^2 y^3)
then:
= log x^2 + log y^3
= 2logx + 3logy
= ....
take over
log (x2 y3)
log(x^2 y^3)
then:
= log x^2 + log y^3
= 2logx + 3logy
= ....
take over