In the production of carbon disulfide (CS2), carbon (C) and sulfur dioxide (SO2) are reacted. If 8.00 g of sulfur dioxide reacts, how many moles of carbon dioxide are produced?
2C+2SO2>> CS2 + CO2
Well, for each mole of SO2, you get one-half mole of CO2
MolesCO2=1/2 * 8/molmassSO2
To determine the number of moles of carbon disulfide (CS2) produced, we need to use the balanced chemical equation for the reaction between carbon (C) and sulfur dioxide (SO2).
The balanced chemical equation for the reaction is:
C + 2SO2 → CS2 + 2CO2
From the balanced equation, we can see that 1 mole of carbon (C) reacts with 2 moles of sulfur dioxide (SO2) to produce 1 mole of carbon disulfide (CS2) and 2 moles of carbon dioxide (CO2).
To find the number of moles of carbon disulfide (CS2) produced, we need to determine the number of moles of sulfur dioxide (SO2) reacted.
First, we need to convert the given mass of sulfur dioxide (SO2) into moles using its molar mass. The molar mass of sulfur dioxide (SO2) is calculated by adding the atomic masses of sulfur (S) and oxygen (O).
The atomic mass of sulfur (S) is 32.06 g/mol, and the atomic mass of oxygen (O) is 16.00 g/mol.
Molar mass of sulfur dioxide (SO2) = (32.06 g/mol) + 2 * (16.00 g/mol) = 64.06 g/mol
Now, we can determine the number of moles of sulfur dioxide (SO2) reacted:
Number of moles of sulfur dioxide (SO2) = (Given mass of SO2) / (Molar mass of SO2)
= 8.00 g / 64.06 g/mol
≈ 0.125 mol
Since the balanced chemical equation tells us that 1 mole of carbon dioxide (CO2) is produced for every 2 moles of sulfur dioxide (SO2) reacted, we can use this ratio to determine the number of moles of carbon dioxide (CO2) produced.
Number of moles of carbon dioxide (CO2) = (0.125 mol SO2) * (2 mol CO2 / 2 mol SO2)
= 0.125 mol CO2
Therefore, 0.125 moles of carbon dioxide (CO2) are produced.