jonathans picture has a perimeter of 38 inches. If the length of the paper is 11 inches what is the width

To find the width of the picture, we need to subtract the length from the total perimeter.

Given:
Perimeter of the picture = 38 inches
Length of the paper = 11 inches

Let's assume the width of the picture is represented by 'w' inches.

Perimeter of a rectangle = 2(length + width)

According to the given information:
38 = 2(11 + w)

Now, let's solve for 'w':

38 = 2(11 + w)
Divide both sides by 2 to isolate the expression:
19 = 11 + w
Subtract 11 from both sides to solve for 'w':
w = 19 - 11
w = 8

Therefore, the width of Jonathan's picture is 8 inches.

To find the width of Jonathan's picture, we need to set up an equation using the given information.

Let the width of the picture be represented by "w" inches.

Perimeter of a rectangle is given by the formula: Perimeter = 2(length + width)

Given that the perimeter of Jonathan's picture is 38 inches and the length is 11 inches, we can set up the equation as follows:

38 = 2(11 + w)

Now, let's solve for the width:

First, simplify the equation by multiplying 2 by (11 + w):

38 = 22 + 2w

Next, subtract 22 from both sides of the equation:

38 - 22 = 2w

16 = 2w

Finally, divide both sides of the equation by 2:

16/2 = w

w = 8

Therefore, the width of Jonathan's picture is 8 inches.

P = 2L + 2W

38 = (2 * 11) + 2W

38 = 22 + 2W

16 = 2W

8 = W

The perimeter of a piece of paper is 38 inches. It’s length is 11 inches