# Math

Two old friends meet. They hadn't seen each other in 22 years. Betty is 6 years older than France's, but neither is older than 50. The sum of their ages when they met is exactly half of their ages today.

How old is Betty?

B= F+6
B=50-22 =28
F =50 -22=28
B=28+6=34

Betty is 34 years old.

Could you please let me know if I worked this out correctly.. I am still a little confused.

Thank you

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1. B = F+6
(B-22)+(F-22) = (B+F)/2

Try that.

Your solution indicates that when they last met, they were 6 and 14.
But 6+14 is not half the sum of their ages today.

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posted by Steve

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