Two charges +1C and -1C are placed at distance 1m apart ,each having masses 2kg respectively are released.what is the type of collision they experience?
To determine the type of collision the charges experience, we need to consider the conservation of momentum and the conservation of kinetic energy during the collision.
The formula to calculate momentum is:
momentum (p) = mass (m) × velocity (v)
Since both charges have the same mass (2kg) and are initially at rest, their initial momentum is zero.
During the collision, the charges will attract each other due to their opposite charges. This will cause them to accelerate towards each other.
Now, let's consider the conservation of kinetic energy:
The formula to calculate kinetic energy is:
kinetic energy (KE) = 1/2 × mass (m) × (velocity (v))^2
Before the collision, the charges are at rest, so the initial kinetic energy is also zero.
During the collision, as the charges move towards each other, they gain speed and their kinetic energy increases.
Since the charges have opposite charges and are attracted to each other, they will continue to move towards each other after the collision.
In this scenario, the charges initially at rest gain kinetic energy and continue to move towards each other after the collision. This type of collision is known as an inelastic collision.
Therefore, the charges experience an inelastic collision.