An artist has 8 square feet of canvas to paint. The canvas was rectangular and the length was twice as long as the width. How long was the canvas?
A = LW
What are the factors of 8?
To find the length of the canvas, we can set up an equation based on the given information.
Let's assume the width of the canvas is x feet. Since the length is twice as long as the width, we can say that the length = 2x feet.
The formula for the area of a rectangle is length times width. In this case, the area of the canvas is given as 8 square feet. So we can set up the equation:
Length * Width = Area
(2x) * (x) = 8
2x^2 = 8
To solve for x, divide both sides of the equation by 2:
x^2 = 4
Now, take the square root of both sides of the equation:
√(x^2) = √(4)
x = 2
Therefore, the width of the canvas is 2 feet. Since the length is twice as long as the width, the length of the canvas is:
2 * 2 = 4 feet
So, the canvas is 2 feet wide and 4 feet long.