Calculus quick question pls

Why is there no vertical asymptote on

F(x) = x/(x^2+1)

What i learned is that to find vertical asymptote you have to set the denominator To 0 and solve for x ?
In that case I find that x=-1,1

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1. vertical asymptotes occur when you try to divide by zero.

x^2+1 is never zero.

You solved for x^2-1 = 0

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posted by Steve
2. I don't get it ?

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posted by Amelia
3. huh? huh? How can you say that?

x^2 is always positive, right? At least it is never negative.

So, x^2+1 is always positive, and always at least 1.

So, dividing by x^2+1 will never yield a vertical asymptote.

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posted by Steve
4. Yesss okay thank you sir

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posted by Amelia

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