In the lab we synthesised nickel (II) ammine tetraflouroborate using hydrated nickel chloride and ammonia then this solution was added to a slotion of ammonia and ammonium tetraflouroborate,now im struggling to write a fully balanced chemical reaction.Would anyone please help with the equation?
NiCl2.6H2O + 6NH3 ==> Ni(NH3)6Cl2 + 6H2O
Ni(NH3)6Cl2 + 2NH4BF4 ==> [Ni(NH3)6][BF4]2 + 2NH4Cl
Add the two equations to obtain an overall equation if that's what you want.
By the way I think your spelling of tetrafluoroborate is incorrect.
Sure! I can help you write the fully balanced chemical reaction for the synthesis of nickel (II) ammine tetrafluoroborate. Here's how you can approach it:
Step 1: Identify the reactants and products.
The reactants in this reaction are hydrated nickel chloride (NiCl2 · xH2O), ammonia (NH3), and ammonium tetrafluoroborate (NH4BF4). The product is nickel (II) ammine tetrafluoroborate.
Step 2: Write the molecular formula for each compound.
The molecular formula of hydrated nickel chloride is NiCl2 · xH2O. The molecular formula of ammonia is NH3, and ammonium tetrafluoroborate is NH4BF4. Nickel (II) ammine tetrafluoroborate can be represented as [Ni(NH3)4](BF4)2.
Step 3: Balance the equation.
To balance the equation, we need to ensure that the number of each type of atom is the same on both sides. Let's write the equation:
NiCl2 · xH2O + NH3 + NH4BF4 → [Ni(NH3)4](BF4)2 + HCl + H2O
Step 4: Balance the nickel (Ni) atoms.
There is one nickel atom on the left side and one on the right side, so nickel is already balanced.
Step 5: Balance the chlorine (Cl) atoms.
There are two chlorine atoms in nickel chloride (NiCl2) and one chlorine atom in hydrogen chloride (HCl). To balance the chlorine atoms, we add a coefficient of 2 in front of HCl:
NiCl2 · xH2O + NH3 + NH4BF4 → [Ni(NH3)4](BF4)2 + 2HCl + H2O
Step 6: Balance the hydrogen (H) atoms.
There are four hydrogen atoms in ammonia (NH3) and two hydrogen atoms in water (H2O). To balance the hydrogen atoms, we add a coefficient of 4 in front of H2O:
NiCl2 · xH2O + NH3 + NH4BF4 → [Ni(NH3)4](BF4)2 + 2HCl + 4H2O
Step 7: Balance the boron (B) and fluorine (F) atoms.
There is one boron atom and four fluorine atoms in ammonium tetrafluoroborate (NH4BF4). To balance these atoms,we add a coefficient of 2 in front of NH4BF4:
NiCl2 · xH2O + NH3 + 2NH4BF4 → [Ni(NH3)4](BF4)2 + 2HCl + 4H2O
And there you have it! The fully balanced chemical reaction for the synthesis of nickel (II) ammine tetrafluoroborate is:
NiCl2 · xH2O + NH3 + 2NH4BF4 → [Ni(NH3)4](BF4)2 + 2HCl + 4H2O