A man invests rs6750,partly in shares of 6% at rs140 and partly in shares of 5% at rs 125.if his total income is rs280,how much has he invested in each?

How come u r using divident % in investment.It is used in nominal value

understandable bilkul nahi hai 😤🤔🤯🤯

To solve this problem, we can use algebraic equations. Let's assume the man invests Rs. x in shares of 6% at Rs. 140 and Rs. y in shares of 5% at Rs. 125.

According to the information given, the total investment is Rs. 6750, so we have the equation:

x + y = 6750 ----(equation 1)

The man's total income from these investments is Rs. 280. We can calculate the income from each investment with the following equation:

0.06x + 0.05y = 280 ----(equation 2)

Now we have a system of two equations with two variables. We can solve this system by substitution or elimination.

Let's use the elimination method to solve these equations:

Multiply equation 2 by 100 to eliminate decimals:

6x + 5y = 28000 ----(equation 3)

Now, we can subtract equation 1 from equation 3 to eliminate the variable 'x':

(6x + 5y) - (x + y) = 28000 - 6750
5x + 4y = 21250 ----(equation 4)

We now have two linear equations:

x + y = 6750 ----(equation 1)
5x + 4y = 21250 ----(equation 4)

Solving these equations, we find:

Multiply equation 1 by 4:

4x + 4y = 27000 ----(equation 5)

Subtract equation 5 from equation 4 to eliminate variable 'y':

(5x + 4y) - (4x + 4y) = 21250 - 27000
x = -5750

Substituting this value of x into equation 1, we find:

-5750 + y = 6750
y = 12500

So, the man has invested Rs. 5750 in shares of 6% at Rs. 140 and Rs. 12500 in shares of 5% at Rs. 125.

shares bought at RS140 --- x

shares bought at RS125 --- y

amount invested at 6% --- 140x
amount invested at 5% --- 125y

140x + 125y = 6750 **

.06(140x) + .05(125y) = 280
8.4x + 6.25y = 280
times 20
168x + 125y = 5600 ***

subtract ** from ***
28x = -1150

not possible.
Unless you can find an error in my calculations, this question is bogus