Precal

Solve the equation:
Logx=1-log(x-3)

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asked by Bobbie
  1. log x + log (x-3) = 1

    log (x^2 -3x) = 1

    10^log (x^2 -3x) = 10^1 = 10

    x^2 -3 x -10 = 0

    (x-5)(x+2) = 0

    x = +5 or - 2

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    posted by Damon
  2. but -2 is not a solution, since the domain of log(x) is x>0.

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    posted by Steve

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