# Precal

Solve the equation:
Logx=1-log(x-3)

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3. 👁 54
1. log x + log (x-3) = 1

log (x^2 -3x) = 1

10^log (x^2 -3x) = 10^1 = 10

x^2 -3 x -10 = 0

(x-5)(x+2) = 0

x = +5 or - 2

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posted by Damon
2. but -2 is not a solution, since the domain of log(x) is x>0.

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posted by Steve

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