,I NEED TO DRAW A LEWIS STRUCTURE for C2n2,cyanogen,and to state the noble gas,i know the answer is neon,but i have far to many electrons and am getting the gas argon,please help
:N:::C:C:::N:
please where do u think i am going wrong
I don't know. You didn't show any work.
C has 4 electrons.
N has 5 electrons.
Total of 9 x 2 = 18 electrons.
Count those around the structure I drew and there are 18. I don't unsderstand the part of the question about noble gas structures. I am familiar with atoms becoming isoelectronic with noble gases but I've never applied that to molecules.
18 is what i got to,thanks for your time Dr bob
i like men
You're welcome! Based on the Lewis structure you provided, there are two carbon atoms (C) connected by a triple bond and two nitrogen atoms (N) connected to each carbon atom by a single bond. In order to find the total number of electrons needed, you can add up the valence electrons for each individual atom involved.
Each carbon atom has four valence electrons, and there are two carbon atoms, so that gives us a total of 8 electrons. Each nitrogen atom has five valence electrons, and there are two nitrogen atoms, so that gives us another total of 10 electrons. Adding those up, we get a total of 18 valence electrons for the cyanogen molecule (C2N2).
Now, to distribute these electrons around the Lewis structure, start by connecting the atoms with single bonds. In this case, you have two C-N single bonds. Each bond uses two electrons, so that accounts for 4 electrons. Place the remaining 14 electrons around the atoms as lone pairs, making sure to satisfy the octet rule (except for hydrogen, which only needs 2 electrons).
After distributing all the electrons, the structure should resemble what you initially drew:
:N:::C:C:::N:
Now, as for the noble gas state, I assume you wanted to know which noble gas has a similar electron configuration to the cyanogen molecule. In this case, the electron configuration of neon (Ne) is closest to the electron distribution of cyanogen. Both neon and cyanogen have a total of 18 electrons.
I hope this clarifies the process of drawing a Lewis structure for C2N2 and understanding the concept of noble gas electron configurations. Let me know if there's anything else I can assist you with!