calculate the molarity of a NaOH solution that requires 42.55 mL to neutralize 3.53 grams of KHP

KHP + NaOH ==> H2O + NaKP

mols KHP = grams/molar mass = ?
Look at the coefficients in the balanced equation; it is 1:1 so ? mols KPH = same mols NaOH.
Then M NaOH = mols NaOH/

To calculate the molarity (M) of a solution, you need to know the number of moles of solute and the volume of the solution in liters.

In this case, the solute is NaOH, and the volume of the solution in liters is given as 42.55 mL (or 0.04255 L).

First, let's find the number of moles of NaOH used to neutralize KHP (potassium hydrogen phthalate).

1. Determine the molar mass of KHP (C8H5KO4):
- Atomic mass of Carbon (C) = 12.01 g/mol
- Atomic mass of Hydrogen (H) = 1.01 g/mol
- Atomic mass of Potassium (K) = 39.10 g/mol
- Atomic mass of Oxygen (O) = 16.00 g/mol

Therefore, the molar mass of KHP is:
(8 x 12.01 g/mol) + (5 x 1.01 g/mol) + 39.10 g/mol + (4 x 16.00 g/mol) = 204.23 g/mol

2. Convert the mass of KHP to moles:
Given mass of KHP = 3.53 grams
Moles of KHP = (given mass of KHP) / (molar mass of KHP)
Moles of KHP = 3.53 g / 204.23 g/mol

Now, we need to find the number of moles of NaOH since they react in a 1:1 ratio:

Moles of NaOH = Moles of KHP

3. Now, calculate the molarity (M) of the NaOH solution:
Molarity (M) = Moles of NaOH / Volume of Solution (in liters)
Molarity (M) = Moles of NaOH / 0.04255 L

To summarize:
- Find the number of moles of KHP: 3.53 g / 204.23 g/mol
- The number of moles of NaOH is the same as KHP since they react in a 1:1 ratio
- Calculate the molarity of NaOH: Moles of NaOH / 0.04255 L