A 15.0mL sample of an H2SO4 solution is titrated with 24.0 mL of a 0.245 Molarity NaOH solution. What is the molarity of the H2SO4 solution?

H2SO4 + 2NaOH ==> 2H2O + Na2SO4

mols NaOH = M x L = ?
Using the coefficients in the balanced equation, convert mols NaOH to mols H2SO4.
Then M H2SO4 = mols H2SO4/L H2SO4 = ?

To determine the molarity (M) of the H2SO4 solution, we can use the equation:

M1V1 = M2V2

Where:
M1 = molarity of NaOH solution (0.245 M)
V1 = volume of NaOH solution used (24.0 mL)
M2 = molarity of H2SO4 solution (unknown)
V2 = volume of H2SO4 solution used (15.0 mL)

Rearranging the equation, we have:

M2 = (M1V1) / V2

Let's plug in the known values into the equation:

M2 = (0.245 M * 24.0 mL) / 15.0 mL

Now we can calculate the molarity:

M2 = (5.88 mol/L * mL) / mL

M2 = 5.88 M

Therefore, the molarity of the H2SO4 solution is 5.88 M.