Determine the pH of a solution made by diluting 25mL of 6.0 M HCl until the final volume of the solution is 1.75 L
mL1 x M1 = mL2 x M2
25 x 6.0 = 1750 mL x M2
Solve for M of diluted HCl.
Then pH = -log (HCl)
1.07
1.1 with sigfigs
Well, pH is a measure of how acidic or basic a solution is. To determine the pH, we need to know the concentration of H+ ions in the solution.
In this case, we're diluting 25 mL of 6.0 M HCl to a final volume of 1.75 L. Since we're diluting the solution, the concentration of H+ ions will also decrease, but the number of moles of H+ ions will stay the same.
First, let's calculate the number of moles of H+ ions in the 25 mL of 6.0 M HCl:
Moles of H+ ions = concentration (M) x volume (L)
= 6.0 M x 0.025 L
= 0.15 moles
Next, let's calculate the new concentration of H+ ions after dilution:
New concentration of H+ ions = moles / final volume (L)
= 0.15 moles / 1.75 L
≈ 0.0857 M
Finally, we can calculate the pH using the formula:
pH = -log[H+]
pH = -log(0.0857)
≈ 1.07
So, the pH of the solution would be around 1.07. But remember, pH values can be sensitive clowns, so handle them with care!
To determine the pH of the solution, we need to calculate the concentration of H+ ions in the diluted solution.
First, we will use the dilution formula:
C1V1 = C2V2
Where:
C1 = Initial concentration
V1 = Initial volume
C2 = Final concentration
V2 = Final volume
In this case, we know:
C1 = 6.0 M (initial concentration)
V1 = 25 mL (initial volume)
C2 = ? (final concentration)
V2 = 1750 mL (final volume)
However, we need to convert the initial and final volumes to liters because the concentration is given in Molarity (moles per liter).
V1 = 25 mL = 0.025 L
V2 = 1750 mL = 1.75 L
Next, we can plug in these values into the dilution formula:
(6.0 M)(0.025 L) = C2(1.75 L)
Simplifying this equation, we get:
0.15 M = C2
So, the final concentration of the solution is 0.15 M.
Now, we can calculate the pH using the equation:
pH = -log[H+]
The [H+] represents the concentration of H+ ions. In this case, it is 0.15 M.
Plugging this value into the equation, we get:
pH = -log(0.15)
Using a scientific calculator, we can find that the pH is approximately 0.82.
So, the pH of the solution made by diluting 25 mL of 6.0 M HCl until the final volume of the solution is 1.75 L is approximately 0.82.