A charge +4 micro colombs is transferred in a uniform electric field of 200N/C between two points separated by a distance of 20cm. calculate the potential difference between the two points ?
To calculate the potential difference between the two points, we can use the formula:
Potential difference (V) = Electric field strength (E) * Distance (d) * Charge (Q)
Given:
Electric field strength (E) = 200 N/C
Distance (d) = 20 cm = 0.2 m
Charge (Q) = +4 μC = 4 * 10^-6 C
Substituting the values into the formula:
V = 200 N/C * 0.2 m * 4 * 10^-6 C
Now let's calculate the value of V:
V = 200 * 0.2 * 4 * 10^-6 = 0.16 V
Therefore, the potential difference between the two points is 0.16 volts.