Calculate the minimum volume oxygen gas that is required for the complete combustion of a mixture of 20cm carbon monoxide and hydrogen gas
20 cm is a length.
How much H2 gas is there?
To calculate the minimum volume of oxygen gas required for the complete combustion of a mixture of carbon monoxide (CO) and hydrogen (H2) gas, we need to use the balanced chemical equation for the combustion reaction.
First, let's write the balanced chemical equation for the combustion of carbon monoxide:
2CO + O2 → 2CO2
Next, let's write the balanced chemical equation for the combustion of hydrogen gas:
2H2 + O2 → 2H2O
From the balanced equations, we can see that for the combustion of one mole of carbon monoxide (CO), two moles of oxygen gas (O2) are required. Similarly, for the combustion of two moles of hydrogen gas (H2), one mole of oxygen gas (O2) is required.
Using the concept of stoichiometry, we can calculate the amount of oxygen gas required for the given mixture:
Given: Mixture contains 20 cm3 of carbon monoxide (CO) and hydrogen gas (H2)
To convert from cm3 to moles, we will need the molar volume of a gas at standard temperature and pressure (STP). The molar volume of an ideal gas at STP is approximately 22.4 L/mol.
First, calculate the moles of carbon monoxide (CO):
Moles of CO = Volume of CO / Molar volume of CO at STP
= 20 cm3 / 1000 cm3/L (converting cm3 to L)
= 0.02 L / 22.4 L/mol (dividing by molar volume at STP)
= 0.000893 moles
Now, calculate the moles of hydrogen gas (H2):
Moles of H2 = Volume of H2 / Molar volume of H2 at STP
= 20 cm3 / 1000 cm3/L (converting cm3 to L)
= 0.02 L / 22.4 L/mol (dividing by molar volume at STP)
= 0.000893 moles
Since the combustion of carbon monoxide (CO) and hydrogen gas (H2) occurs in the ratio of 2:1 with oxygen gas (O2), the moles of oxygen required can be determined by multiplying the moles of carbon monoxide and hydrogen gas by their respective stoichiometric coefficients:
Moles of O2 = (2 * Moles of CO) + (1 * Moles of H2)
= (2 * 0.000893) + (1 * 0.000893)
= 0.003579 moles
Finally, convert the moles of oxygen gas back into volume using the molar volume at STP:
Volume of O2 = Moles of O2 * Molar volume of O2 at STP
= 0.003579 moles * 22.4 L/mol
= 0.0801656 L
≈ 80 cm3
Therefore, the minimum volume of oxygen gas required for the complete combustion of the given mixture of carbon monoxide and hydrogen gas is approximately 80 cm3.