Jennifer flipped a pair of coins 60 times. On 24 occasions, heads appeared on both coins. How is this outcome different from the expected outcome?
A) It occurred 6 fewer times than expected.
It occurred 4 more times than expected.
It occurred 9 more times than expected.
It occurred 4 fewer times than expected.
Thanks!
To determine the expected outcome, we need to consider the probability of getting heads on both coins in a single flip. Since there are two possible outcomes for each coin flip (heads or tails), the probability of getting heads on both coins is the product of the probabilities of getting heads on each individual coin.
The probability of getting heads on a single coin is 1/2 (assuming a fair coin), so the probability of getting heads on both coins is (1/2) * (1/2) = 1/4.
To find the expected outcome, we multiply this probability by the number of times Jennifer flipped the pair of coins: (1/4) * 60 = 15.
Given that Jennifer observed heads on both coins 24 times, we can calculate the difference between the observed outcome and the expected outcome: 24 - 15 = 9.
Therefore, the correct answer is:
C) It occurred 9 more times than expected.
expected=1/2 * 1/2=1/4
expected number = 60/4=30
so it occured...