Madison has 48 ft of fence with which to fence in a rectangular garden.
What is the maximum area she can enclose?
The maximum area would be a square.
P = 2L + 2W
A = LW
I do not get what you are saying.
Perimeter = 2 times the length + 2 times the width
Each side could be
12 by 12 (24 + 24 = 48)
10 by 14 (20 + 28 = 48)
8 by 16 (16 + 32 = 48)
Multiply the possible lengths and widths together to get the area.
Can u explain the question to me Ms. Sue?
The question asks you for the largest area you can enclose with 48 feet of fencing.
To find the maximum area Madison can enclose with the given amount of fence, we need to determine the dimensions of the rectangular garden that would result in the largest possible area.
Let's suppose the length of the garden is x feet. In that case, the width of the garden would be (48 - 2x) feet, considering that the fence needs to go all the way around the garden, minus the lengths of the two opposite sides.
The formula to calculate the area of a rectangle is: Area = length × width. Therefore, the area of the garden can be expressed as:
Area = x × (48 - 2x)
To find the maximum area, we can differentiate this equation with respect to x and set the derivative equal to zero. This will give us the value of x that maximizes the area.