Given a normal population whise mean is 50 and whise standard deviation is 5, find the probability that a random sample of 25 has a mean greater than 52.

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  1. Z = (52-50)/SEm

    SEm = SD/sqrt n

    Look up Z in table in back of your text labeled area under normal distribution.

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    posted by PsyDAG
  2. 0.9772

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    posted by retha

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