a 2x10^-6 point charge travels a distance of.002m between two parallel charged plates from the negative end toward the positive end. The field has a strength of 500 N/C What is the change in voltage?
PE = Eq/d (Change in voltage is PE)
Sorry should just be V = Ed
End of the day....
To find the change in voltage, we can use the formula:
ΔV = Ed
where ΔV is the change in voltage, E is the electric field strength, and d is the distance traveled.
Given:
Electric field strength (E) = 500 N/C
Distance traveled (d) = 0.002 m
Substituting these values into the formula:
ΔV = (500 N/C) * (0.002 m)
ΔV = 1 N*m/C = 1 Volt
Therefore, the change in voltage is 1 Volt.