physics

A ball is thrown with a horizontal velocity of 2 m/s from a vertical height of 50 m above ground. neglect air resistance and determine:
the horizontal displacement traveled by the ball. can someone please explain this to me!

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asked by Karen
  1. One needs to find how long it is in the air, the initial height determines that.
    h=1/2 g t^2

    Then, knowing the time in air, the horizontal distance is

    d=vhorizontal*time

  2. Thanks!! Could you explain this one to me?

    object is projected with a horizontal velocity of 30 m/s. if it hits the ground 5 seconds later, calculate:
    The height from which the particle was projected.

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    posted by Karen
  3. h=1/2 g t^2
    memorize that equation.

    calculate height.

  4. thanks!

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    posted by Karen

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